Find the perpendicular distance from the point (1,2,3) to the plane x-2y-z=1
One method: find the equation of the line throughout (1,2,3) perpendicular to the plane. Find the intersection of this line and the plane
The Attempt at a Solution
I know the vector (1,-2,-1) is a vector perpendicular to the plane
I'm not sure how to find the distance between where the vector intersects the
plane to the point.
I know what to do if the vector was a line, but I am confused as to how to change the vector into a line.