Perpendicular distance from point to a plane

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SUMMARY

The discussion focuses on calculating the perpendicular distance from the point (1,2,3) to the plane defined by the equation x - 2y - z = 1. The method involves determining the line that passes through the point and is perpendicular to the plane, represented by the vector (1,-2,-1). The correct parametric equations for this line are x = 1 + t, y = 2 - 2t, and z = 3 - t. The next step is to find the intersection of this line with the plane to compute the distance.

PREREQUISITES
  • Understanding of vector equations and their representation
  • Knowledge of parametric equations of lines
  • Familiarity with the concept of planes in three-dimensional space
  • Basic skills in solving systems of equations
NEXT STEPS
  • Learn how to find the intersection of a line and a plane in 3D space
  • Study the derivation of the distance formula from a point to a plane
  • Explore vector projections and their applications in geometry
  • Review examples of solving similar problems involving points and planes
USEFUL FOR

Students studying geometry, particularly those tackling three-dimensional coordinate systems, as well as educators looking for examples of vector and plane interactions.

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Homework Statement


Find the perpendicular distance from the point (1,2,3) to the plane x-2y-z=1
One method: find the equation of the line throughout (1,2,3) perpendicular to the plane. Find the intersection of this line and the plane


The Attempt at a Solution


I know the vector (1,-2,-1) is a vector perpendicular to the plane
I'm not sure how to find the distance between where the vector intersects the
plane to the point.

I know what to do if the vector was a line, but I am confused as to how to change the vector into a line.
 
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I think the line for the vector (1,-2,-1) that goes through P (1,2,3) is:
x=1+t y=2-2t z=3-t

Is this correct?
 

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