Distance from sources of different intensity to get same loudness

  • Thread starter Thread starter coconut62
  • Start date Start date
  • Tags Tags
    Intensity Sources
coconut62
Messages
161
Reaction score
1

Homework Statement



A point source of sound emits energy equally in all directions at a constant rate and a person 8m from the source listens. After a while, the intensity of the source is halved. If the person wishes the sound to seem as loud as before, how far should he be now from the source?

A) 2m B) 2√2m C) 4m D) 4√2m

Homework Equations



Intensity (proportional sign) 1/distance[itex]^{2}[/itex]

Intensity (proportional sign) amplitude (not sure if needed)

The Attempt at a Solution



Answer: D

I = k/d[itex]^{2}[/itex] , where k is a constant.

I= k/8[itex]^{2}[/itex]

k = 64 I

(new I) x (new d[itex]^{2}[/itex]) = 64 I

(0.5 I) x new d[itex]^{2}[/itex] = 64I

new d[itex]^{2}[/itex]= 128

new d = 8√2 (no answer)

Sounds not very logical, but I don't know how am I wrong. Please explain to me.
 
In your expression I = k/d^2 what symbol represents the intensity of the source?

Your answer is obviously wrong. The naswer has to be < 8m!
 
I represents intensity.
 
The intensity of the source does not depend on distance from the source.
Review your formulas. You must have one that relates the power emitted by the source with the intensity received at a given distance.
 
coconut62 said:
I represents intensity.

No, I represents intensity at the location d. In other words, I = I(d).
 
I think this is the formula needed:

Intensity = Power/4∏r[itex]^{2}[/itex]

So the intensity of the sound where the person stood was P/256∏.

It is now halved. So the power gets halved too.

P= 128∏I

since P = 4∏r[itex]^{2}[/itex]I

128∏I=4∏r[itex]^{2}[/itex]I

r=4√2

Please correct me if I'm wrong.
 
coconut62 said:
i think this is the formula needed:

Intensity = power/4∏r[itex]^{2}[/itex]

so the intensity of the sound where the person stood was p/256∏.

It is now halved. So the power gets halved too.

P= 128∏i

since p = 4∏r[itex]^{2}[/itex]i

128∏i=4∏r[itex]^{2}[/itex]i

r=4√2

please correct me if I'm wrong.

a-ok!
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
4K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
11
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 11 ·
Replies
11
Views
4K
  • · Replies 1 ·
Replies
1
Views
5K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K