Distance of compass to wire based on magnetic field strength

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SUMMARY

The discussion focuses on the relationship between the distance of a compass from a current-carrying wire and the resulting magnetic field strength. When no current flows through the wire, the compass needle aligns parallel to the wire. However, when current flows, the needle deflects, indicating the influence of the magnetic field generated by the wire. The magnetic field strength can be calculated using the formula B = (μo I) / (2πd), which relates the current (I) and distance (d) to the magnetic field (B) affecting the compass.

PREREQUISITES
  • Understanding of magnetic fields and their properties
  • Familiarity with the Biot-Savart Law
  • Knowledge of compass mechanics and magnetic north
  • Basic algebra for manipulating equations
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  • Study the Biot-Savart Law for calculating magnetic fields around current-carrying conductors
  • Learn about the principles of magnetic field strength and its effects on compass behavior
  • Explore the relationship between current intensity and magnetic field strength
  • Investigate the concept of magnetic field lines and their visualization
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Students in physics, electrical engineering majors, and anyone interested in understanding the effects of magnetic fields on compass navigation and current-carrying conductors.

songoku
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Homework Statement


As shown in Figure 1 below, a long, straight conducting wire is stretched horizontally directly above a magnetic compass, both of which are separated by distance d. When electrical current is not flowing through the wire, the compass needle points in a direction parallel with the wire’s direction. When a current flows through the wire, the north pole of the needle rotates 60o to the east and comes to rest. Next, as shown in Figure 2, while the current continues to flow, the wire is moved vertically upward to a position distance from the compass. As a result, the north pole of the needle rotates and comes to rest position pointing 45o east of north. What is the value of D/d ?
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Homework Equations


Maybe:

B = (μo I) / (2πd)

The Attempt at a Solution


The compass in figure 1 has bigger angle because the magnetic field is stronger but I don't know what formula relates the value of magnetic field produced by a very long straight wire to the angle of deflection of compass.
 
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Why do you suppose the compass was pointing in the direction it was when there was no current in the wire (what does a compass "measure")?
 
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gneill said:
Why do you suppose the compass was pointing in the direction it was when there was no current in the wire (what does a compass "measure")?

Ah I get it. Thanks a lot for the hint
 
You're very welcome :smile:
 

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