Distance on arrays of unit-quaternions

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mnb96
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Hello,
let's take the algebra of quaternions [itex]\mathcal{C}\ell_{3,0}^+[/itex] and consider only the sub-algebra of unit-quaternions.
When we wanted to define a https://www.physicsforums.com/showpost.php?p=2911801&postcount=6" we used the fact that unit-quaternions lie on the [itex]\mathcal{S}^3[/itex] sphere.

Now, what happens if we instead consider the whole set of finite "arrays" [itex](q_1,\ldots,q_n)[/itex], in which each entry qi is a unit-quaternion?

Is it possible that an n-tuple [itex](q_1,\ldots,q_n)[/itex] represent a point on some manifold?
If so, how can we compute the geodesic distance between two n-tuples?

Thanks!


EDIT:
a simplified question could be: given a vector of unit complex numbers, can we consider this vector as a point of some manifold?
 
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mnb96 said:
Hello,
let's take the algebra of quaternions [itex]\mathcal{C}\ell_{3,0}^+[/itex] and consider only the sub-algebra of unit-quaternions.
When we wanted to define a https://www.physicsforums.com/showpost.php?p=2911801&postcount=6" we used the fact that unit-quaternions lie on the [itex]\mathcal{S}^3[/itex] sphere.

Now, what happens if we instead consider the whole set of finite "arrays" [itex](q_1,\ldots,q_n)[/itex], in which each entry qi is a unit-quaternion?

Is it possible that an n-tuple [itex](q_1,\ldots,q_n)[/itex] represent a point on some manifold?
Yes. We can simply consider direct products. Here are some equivalent presentations:
https://www.physicsforums.com/insights/journey-manifold-su2mathbbc-part/
If so, how can we compute the geodesic distance between two n-tuples?
Depends on the metric considered.
Thanks!EDIT:
a simplified question could be: given a vector of unit complex numbers, can we consider this vector as a point of some manifold?
There is a difference between a vector and a point so your question is a bit unclear. Every point described via coordinates can be considered a point of a manifold. Which manifold might be the more interesting question as there is no unique answer.