A Cessna 150 averages 150 mph in still air. With a tailwind it is able to make a trip in 2 1/3 hours. Because of the headwind, it is only able to make the return trip in 3 1/2 hours. What is the average wind speed?
(1) If x = wind speed and y = still air speed
∴ resultant speed (tailwind) = x + y
∴ resultant speed (headwind) = x - y
(2) d = rt
The Attempt at a Solution
let x = wind speed
still air speed = 150 mph
tailwind time = 2 1/3 hours
tailwind speed = 150 + x
headwind time = 3/12 hours
headwind speed = 150 - x
I used these as given for the problem, expressed distance in terms of tailwind/headwind time and rates, set distance as constant (equates), solves for x then gets 57.69 as answer.
but in the book, the answer is 30 mph. What is the problem with my solution?
Thanks in advance.