Seems OKmattykay said:Part 1 was to determine acceleration, which is 2 m/(s^2)
Show what you've done.The Attempt at a Solution
I've come up with 44, 41, 19, and 83 meters, all of which have been wrong.
To calculate distance using acceleration and time, you can use the formula d = 1/2at^2, where d is the distance, a is the acceleration, and t is the time.
The unit for distance when using acceleration and time is meters (m).
Yes, if the initial velocity is not given, you can use the formula d = at^2, where d is the distance, a is the acceleration, and t is the time.
The greater the acceleration, the greater the distance traveled in a given amount of time. This means that the object is moving faster and covers more distance in the same amount of time.
No, the formula for distance using acceleration and time (d = 1/2at^2) is only valid for uniform acceleration, where the acceleration remains constant. For non-uniform acceleration, you would need to use a different formula, such as the trapezoidal rule or the average velocity formula.