Distance using acceleration and time

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Homework Help Overview

The discussion revolves around a problem involving a car's acceleration from 15 m/s to 28 m/s over a duration of 6.4 seconds, with the goal of determining the distance traveled during this time. The subject area is kinematics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss various attempts to calculate distance, mentioning different results and methods. Some suggest using average speed or kinematic equations, while others inquire about the use of a velocity-time graph to find the distance.

Discussion Status

The discussion is ongoing, with participants exploring different approaches and questioning the methods used. Some guidance has been offered regarding the use of specific formulas, but there is no explicit consensus on the correct approach yet.

Contextual Notes

Participants have expressed uncertainty about their calculations and the formulas applicable to the problem, indicating a need for clarification on the correct method to use.

mattykay
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Homework Statement


A car accelerates from 15 m/s to 28 m/s in 6.4 s. How far did it travel in this time?

Homework Equations


Unsure- have tried several, and all results have been wrong
Part 1 was to determine acceleration, which is 2 m/(s^2)

The Attempt at a Solution


I've come up with 44, 41, 19, and 83 meters, all of which have been wrong.
 
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mattykay said:
Part 1 was to determine acceleration, which is 2 m/(s^2)
Seems OK

The Attempt at a Solution


I've come up with 44, 41, 19, and 83 meters, all of which have been wrong.
Show what you've done.

There are several ways to solve this. One way is to use the average speed.
 
Do you know your kinematic equations?

Alternatively, if you plot a v-t graph, do you know how to obtain the distance traveled from that graph?
 
I got it; I was using one formula, when I should have been using d=((vf+vi)/2)*t
 
Using d=ut + 1/2 at2 should have given the same answer.
 

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