Distribution Function for 1/2X and (lambda)X

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Homework Help Overview

The discussion revolves around determining the distribution function of the random variable (1/2)X, where X follows an exponential distribution with a rate parameter of 1/2. Additionally, there is a related question regarding the distribution function of (lambda)X when X has an exponential distribution with parameter lambda.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants explore the implications of the expression (1/2)X versus 1/(2X) and clarify the notation. One participant attempts to relate the distribution of (1/2)X to the distribution of X, suggesting a transformation approach. Another participant raises a similar question regarding (lambda)X.

Discussion Status

The discussion is ongoing, with participants clarifying notation and exploring the implications of their assumptions. Some guidance has been offered regarding the transformation of the random variable, but no consensus or resolution has been reached yet.

Contextual Notes

Participants are working under the constraints of homework rules, which may limit the depth of exploration and the information available for the problem. The exact nature of the exponential distribution and its properties are assumed to be known by the participants.

JosephLee
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Homework Statement



Let X have an Exp(1/2) distribution. Determine the distribution function of 1/2X. What kind of distribution does 1/2X have?


The Attempt at a Solution



I can't seem to do this quite properly. I thought of doing the integral from x to -inf of 1/2X dx but that doesn't seem right. I know what a exponential distribution is but nothing else from there.

Is it just something like X = exp(1/2) therefore 1/2X = exp(1/4) or something along those lines?


thanks for the help in advance.
 
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Does 1/2X mean (1/2)X or 1/(2X)? I guess I will assume the former. Parentheses do serve a purpose you know.

If Y = (1/2)X then P(Y ≤ x) = P((1/2)X ≤ x) = P(X ≤ 2x)

Does that help you?
 
im sorry, its (1/2)X.

Does this change anything?

also along those same lines, there's another part to the question which is exactly the same as above but its:

let X have a exp(lambda) distribution...determine the distribution function of (lambda)X and what kind of distribution does this have?
 
"Does this change anything?"

No, I assumed that.

"also along those same lines, there's another part to the question which is exactly the same as above but its:

let X have a exp(lambda) distribution...determine the distribution function of (lambda)X and what kind of distribution does this have?"

Did you understand my first reply. That should help.
 

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