Divergence of a Magnetic Field not equaling zero

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Homework Help Overview

The discussion revolves around the divergence of a magnetic field, specifically addressing the assertion that the divergence of B (∇·B) equals zero. The original poster expresses confusion regarding the application of divergence in cylindrical coordinates and how it appears to contradict established principles.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to reconcile their calculations of the divergence of B in cylindrical coordinates with the known result that it should equal zero. They question the validity of their assumptions regarding the partial derivatives involved.
  • Some participants question the conditions under which the partial derivatives are considered zero, suggesting that the behavior of vector components may differ between coordinate systems.

Discussion Status

The discussion is ongoing, with participants exploring the implications of coordinate transformations on vector fields. There is an exchange of ideas regarding the nature of vector components in different coordinate systems, but no consensus has been reached yet.

Contextual Notes

The original poster mentions being stuck on the problem for hours, indicating a potential struggle with the underlying concepts of vector calculus in different coordinate systems. There is also an implication that the problem may be part of a larger context involving divergences and curls.

Maliska
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I have a larger problem involving divergences and curls, but the correct answer requires ∇°B (divergence of B) = 0. I understand the proof of this in Griffiths, but the definition of divergence in cylindrical coordinates is:

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After using the product rule to split the first term, we get the divergence of B is B_rho / rho + 0 + 0 + 0, or simply Div(B)=B_rho / rho; however, this clearly contradicts what we know about the divergence of B being zero. Can someone please clarify this for me, I've been stuck at it for hours.

Thanks.

P.s. First post!
 
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How do you know that the partial derivatives you claim to be zero are zero? Do you have a specific field in mind? A field that's a constant vector in Cartesian can look rather different in polar.
 
Thank you haruspex for responding. The partial derivatives I said equal zero could be my mistake, but please explain how a vector with constant components in cartesian coordinates can have nonzero partial derivatives in cylindrical coordinates.
 
Aρ, for example, refers to the component of the vector in the ρ direction. If the vector is constant, its component in the ρ direction may yet depend on θ and z. It's not that the vector varies, but that the unit ρ-direction vector does.
 

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