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Divergence of a two dimensional 3 order tensor

  1. Feb 21, 2008 #1
    I want to calculate the divergence of a two dimensional 3 order tensor; e.g.

    nabla=(d/dx, d/dy)

    and

    Ax =
    ( C D)
    ( E F),

    Ay =
    ( G H)
    ( I J)

    (it's a 2x2x2 cube).

    Index notation:

    (nabla)_i = d/dx_i

    and elements of A are A_ijk

    How do I contract it properly to calculate

    Divergence of A (Nabla inner product A)?

    Thanks a lot!!
     
  2. jcsd
  3. Feb 24, 2008 #2
    Thanks guys.

    I got the answer.

    You should contract over the first index; so

    $(\nabla\cdot\mathbf{A})_{jk}=\frac{d}{dx_i}A{ijk}$
     
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