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How many grams of Ba(IO3)2 can be dissolved in 700mL of a 0.100M KIO3 solution at 25C? use activity coefficients for this. (Ksp of Ba(IO3)2 =1.57E-9)

my answer:

I used this equation: Ksp = (concentration) * (activity coefficient)

well i found out that my ionic strength of KIO3 is 0.100M and from a chart, i found the respective activity coeff for Ba2+ and IO3-.

Ba2+ ---> 0.38

IO3^- ----> 0.775

Ba(IO3)2 <----> Ba2+ + 2IO3^-

I 0 x 0.100M

C +x +2x

E x 0.100M+2x

using the equation above,

Ksp = [Ba2+]*(activity coeff of Ba) * [IO3^-]^2 * (activity coeff of IO3^-)^2

1.57E-9 = (x)(0.38) * (0.100+2x)^2 * (0.775)^2

so i solve for X and that would be the concentration of Ba(IO3)2 in mol/L

BUT, to solve for X, i found it complicated because there would be 3 solutions for X aren't there?? since it's X^3...... so i am confused on what to do.

help appreciated, Thanks.