Divide a big cube into 49 small cubes

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SUMMARY

The discussion focuses on the mathematical procedure to divide a large cube with a side length of 1 into 49 smaller cubes. The method involves initially dividing the large cube into 343 smaller cubes, each with a side length of $\frac{1}{7}$. From these, 336 cubes are then reconfigured to create 42 cubes with a side length of $\frac{2}{7}$. This results in a total of 49 cubes, comprising 42 smaller cubes and 7 remaining cubes of the original size.

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  • Understanding of geometric principles related to cube division
  • Familiarity with basic algebraic manipulation
  • Knowledge of the OEIS (Online Encyclopedia of Integer Sequences) for reference
  • Concept of cube volume and dimensions
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  • Explore the mathematical properties of cube dissection
  • Research the OEIS sequence A014544 for further insights on cube subdivisions
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Please divide a big cube into 49 small cubes
 
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Albert said:
Please divide a big cube into 49 small cubes

[sp]You can be assumed to follow a procedure of this type. Il the side of big cube is 1, then You first divide it into 343 cubes of side $\frac{1}{7}$. Then You use 336 of them to form 42 cubes of side $\frac{2}{7}$, so that at the end 42+7=49 cubes remain...[/sp]

Kind regards

$\chi$ $\sigma$
 
chisigma said:
[sp]You can be assumed to follow a procedure of this type. Il the side of big cube is 1, then You first divide it into 343 cubes of side $\frac{1}{7}$. Then You use 336 of them to form 42 cubes of side $\frac{2}{7}$, so that at the end 42+7=49 cubes remain...[/sp]

Kind regards

$\chi$ $\sigma$
very good ! here is my solution
if the big cake of side 6
divide the cake into three lays:
the first lay of side 2 (9 cakes)
the second lay of side 1 (36 cakes)
the third lay of side 3 (4 cakes)
9+36+4=49
 

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Last edited:
See A014544 - OEIS for information about the number of sub-cubes into which a cube can be dissected.
 

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