Dividing differential equations

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To derive an expression for X(T) from two second-order differential equations, one can divide the equations after expressing the second derivatives as operators. The user initially struggled with how to handle the second derivatives but realized that treating them as d/da(dX/da) allows for cancellation of the d/da terms when dividing. This simplification leads to a manageable form for solving the resulting equation. Ultimately, the user found that the solution yields an exponential result, X(T) = exp(T/sqrt(2)). The discussion highlights the importance of understanding the manipulation of differential operators in solving such equations.
Hybird
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Homework Statement



This is more of a problem I have with my knowledge of differentials. I have two second order differential equations for variables X(a) and T(a). I want to get an expression for X(T). I know I have to divide them, but how do you go about dividing them if they are explicitly stated as:

eqn1: \frac{d^{2}X}{da^{2}} = Some polynomial

and,

eqn2: \frac{d^{2}T}{da^{2}} = Some polynomial

The Attempt at a Solution



I know for first derivative with respect to 'a', you can just divide them directly and the 'da' part will just cancel, but what would you get for a second derivative?

Example of first derivative would be:

dX/da divided by dT/da would equal dX/dT, and you could just solve the resulting simple differential equation to get X(T).
 
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Ok, maybe I should give the RHS of the equations too..


eqn1: \frac{d^{2}X}{da^{2}} = -X \frac{dT}{da}} \frac{dT}{da}}

eqn2: \frac{d^{2}T}{da^{2}} = \frac{-2}{X^{2}} \frac{dX}{da}} \frac{dT}{da}}
 
Never mind, I'm retarded. I just expressed the second order derivative as :

d/da(dX/da) and when you divide it by d/da(dT/da) the d/da part cancels because its just like an operator. I got an exponential result as X(T) = exp(T/sqrt(2))
 
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