johne1618
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phsopher said:If on the other hand the physical distance is constant between two points in space, as would be the case for the two ends of a rigid rod, then the comoving (coordinate) separation between these two points can't possibly be the same as what it was in the beginning.
Ok - I accept your point that the co-ordinate separation between the ends of a rod with a fixed proper length must change. But I'm not using the rod's changing co-ordinate separation in my argument - I only use the rod's constant proper length.
At time ##t_0## I start with a rigid rod with proper length ##l_0## adjacent to an equal proper length of space ##ds_0##.
As ##a(t_0)=1## we have:
<br /> ds_0 = a(t_0)\ dr_0 \\<br /> ds_0 = dr_0<br />
where ##dr_0## is the co-ordinate length of the space. Therefore at time ##t_0## we have:
<br /> ds_0 = dr_0 = l_0.<br />
Now at time ##t## the proper length of the space is given by:
<br /> ds = a(t)\ dr_0<br />
The rod is rigid so that its proper length is still ##l_0## (I don't care that its co-ordinate length has shrunk accordingly.)
The space is co-moving so that its co-ordinate length ##dr_0## has not changed.
Therefore at time ##t## we still have:
<br /> l_0 = dr_0<br />
and so at time ##t## we can assert:
<br /> ds = a(t)\ l_0.<br />
The cosmological time interval is given by ##dt=a(t)dr_0/c=ds/c## whereas the time interval measured by a rigid light clock, of length ##l_0##, is given by ##d\tau=l_0/c## so that we have finally:
<br /> d\tau = \frac{dt}{a(t)}.<br />
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