Do Joule Thief's Work With Supercapacitors

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SUMMARY

This discussion centers on the feasibility of using a Joule Thief circuit with supercapacitors to boost voltage for small projects. The user faces challenges with a 2.5V supercapacitor, which drops voltage significantly, leading to inefficient power usage. Recommendations include considering low input boost converters like the TPS61200 and LTC3105, which can operate at lower voltages, as well as evaluating the practicality of using a larger supercapacitor instead of adding complexity to the circuit.

PREREQUISITES
  • Understanding of supercapacitor voltage characteristics
  • Familiarity with Joule Thief circuit design
  • Knowledge of boost converter functionality
  • Basic electronics principles, including voltage and energy calculations
NEXT STEPS
  • Research "low input boost converter" options for supercapacitors
  • Explore the design and implementation of Joule Thief circuits
  • Investigate the specifications and applications of the TPS61200 boost converter
  • Learn about the LTC3105 and its capabilities for low voltage operation
USEFUL FOR

Electronics hobbyists, engineers working on low-power projects, and anyone interested in optimizing energy usage from supercapacitors.

Puglife
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I have a supercapcitor to power some of my small projects. The only problem is that the voltage drops gradually, unlike a lithium ion battery, in which the voltage is mostly stable throughout. My boost converter that I am using to boost the voltage up to 5 volts, stops working with an input voltage below 1 volt, and it is a 2.5 volt super capacitor, so the power source dies almost twice as fast, because i can only use a little more than half the power in the cap.

My question was, How would I boost the voltage of my super capacitor up to the usable 1 volt, if it is lower than that? Can I use some sort of Joule Thief with my Super Capacitor? Is their some sort of other method I have not considered?
 
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At 1 V, your supercap has only 1/6.25=16% of its original energy left. Do you need those 16% that urgently, or could a larger capacitor or something else be easier?
 
mfb said:
At 1 V, your supercap has only 1/6.25=16% of its original energy left. Do you need those 16% that urgently, or could a larger capacitor or something else be easier?
My Apologize, I meant to say 2 volts not 1, I miss read the specs.
 
Okay, 25% then. Same question. It is certainly possible to get a bit more out of it, but not much (and certainly not the full 25%). I don't know your other constraints (space, money, weight, ...), but making something bigger is often easier than adding complexity.
 
mfb said:
Okay, 25% then. Same question. It is certainly possible to get a bit more out of it, but not much (and certainly not the full 25%). I don't know your other constraints (space, money, weight, ...), but making something bigger is often easier than adding complexity.
so how would i go about getting more out of it, could i use a joule thief to boost the voltage to a constant 2.5 volts? or is their some other way, because i need as much capacity as possible, and for a small size
 
You can certainly do that, but the setup will need some space as well, especially for the coil. The transistor needs some minimal operating voltage, and will draw significant power. The resistor will also need some power.
This is very vague, but "a small size" is not very precise.
 
mfb said:
You can certainly do that, but the setup will need some space as well, especially for the coil. The transistor needs some minimal operating voltage, and will draw significant power.
This is very vague, but "a small size" is not very precise.
so what kind of decrease in efficiency would i be seeing like 10% ?
 
Puglife said:
so what kind of decrease in efficiency would i be seeing like 10% ?
like overall capacity and storage
 
Depends on details of your setup.
If you have the Joule thief as intermediate step all the time, you have its efficiency loss for the whole discharge - you could even end up with less energy than before. If you want to use it only once the capacitor is below 1 V, you need additional logic for that. I would be surprised if it helps.
 
  • #10
mfb said:
Depends on details of your setup.
If you have the Joule thief as intermediate step all the time, you have its efficiency loss for the whole discharge - you could even end up with less energy than before. If you want to use it only once the capacitor is below 1 V, you need additional logic for that. I would be surprised if it helps.
so is their no other way to step up the voltage then, maybe using some other form of boost converter?
 
  • #14
thanks for the help guys, it is much appreciated
 

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