CWatters
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I calculated that your source should charge a 3.3F cap from 0V to 3V in about 160 seconds ignoring losses. In the charged state it would hold about 14 Joules of energy.
If your load works from 3V down to 0.9 V the capacitor could deliver 60mA for about 115 seconds.
Useful theory...
Q=CV
dQ/dt=CdV/dt
dQ/DT=I
So...
I=CdV/dt
You can rearrange that last equation to calculate a lot of things such as the charge or discharge time given the current, capacitance and allowed change in voltage.
If your load works from 3V down to 0.9 V the capacitor could deliver 60mA for about 115 seconds.
Useful theory...
Q=CV
dQ/dt=CdV/dt
dQ/DT=I
So...
I=CdV/dt
You can rearrange that last equation to calculate a lot of things such as the charge or discharge time given the current, capacitance and allowed change in voltage.