- #1

sams

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According to my understanding, the point A (4,5) is not considered scalar. Am I right?

Thanks in advance...

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- #1

sams

Gold Member

- 84

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According to my understanding, the point A (4,5) is not considered scalar. Am I right?

Thanks in advance...

- #2

fresh_42

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A point is a certain location, here at the coordinates (4,5). We need them to specify it, i.e. to assure that we are talking about the same location. We do this in vector form, that is by its distance and direction from another location which we earlier agreed upon calling the origin. So the description is by a vector, the location itself is not.

According to my understanding, the point A (4,5) is not considered scalar. Am I right?

Thanks in advance...

As a location, it is neither a vector nor a scalar. A scalar would be a single valued valuation, a number. In case every point has such a valuation, e.g. the temperature, this valuation would be the scalar and the set of all pairs (point , temperature) would be a scalar field. You see, that the point itself isn't called a scalar.

So scalars, vectors, matrices, tensors are what happens at a certain location, they can be evaluated at this location or they are simply attached to this location. Their nature, however, is different from the nature of the point, the location. That's more or less the physical point of view. Mathematically a point is just a zero-dimensional object that has nothing to do with scalars or vectors. It's not even located anywhere as long as we do not make assumption on how to describe it.

- #3

jedishrfu

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temp=T(latitude,longitude)

More on scalars:

https://hepweb.ucsd.edu/ph110b/110b_notes/node2.html

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