Does a balloon's temperature increase when a balloon is popped?

Click For Summary
SUMMARY

The experiment demonstrated that when a balloon is popped, the temperature of the air inside typically increases, with recorded changes from approximately 29 degrees Celsius to 29.2 degrees Celsius. This phenomenon can be explained by the Ideal Gas Law (Pv = nRT), where the increase in volume upon popping the balloon outweighs the decrease in pressure. The results indicated a mean temperature increase of about 0.06 degrees Celsius, suggesting that the thermodynamic process of work done on the gas during the popping event contributes to the observed temperature rise.

PREREQUISITES
  • Understanding of the Ideal Gas Law (Pv = nRT)
  • Basic knowledge of thermodynamic processes
  • Familiarity with experimental design and statistical analysis (mean and standard deviation)
  • Experience with data logging and temperature measurement techniques
NEXT STEPS
  • Research the implications of the Ideal Gas Law in real-world applications
  • Explore the concept of work done on gases during expansion and compression
  • Investigate the effects of different balloon materials on experimental outcomes
  • Learn about statistical methods for analyzing experimental data, focusing on mean and standard deviation
USEFUL FOR

Students conducting physics experiments, educators teaching thermodynamics, and researchers interested in gas behavior under varying conditions.

Elizabeth Lil
Messages
2
Reaction score
0

Homework Statement


We blew up a balloon, attached a data logger inside the balloon. We then popped it and checked if the temperature increased or decreased. Most of the time, the temperature increased (from around 29 degrees Celsius to 29.2 degrees Celsius).

Why is this so?


Homework Equations


Ideal Gas Law: Pv= nRT (where n and R are constants)


The Attempt at a Solution


My group is divided. One of us thinks that the balloon's temperature should have decreased, as the pressure decreases (following the Ideal Gas Law up there). But another of us thinks that it should have increased, because the volume increased more than the pressure did.
 
Physics news on Phys.org
Welcome to PF.
What is the thermodynamic process you'd expect to be dominant when the balloon was popped?

What was the mean and standard deviation of the changes over many experiments?
Did you pop the balloon by inflating it until it burst or just pricking it with a pin?
 
Last edited:
We popped the balloon with a pin.

Our results show that the temperature of the air in the balloon either remained the same or increased by about 0.2-0.3 oC, but we're not sure if this is theoretically correct or simply due to human error. The mean over all our experiments should be around an increase of 0.06 oC or so.

If our results are correct, then I suppose the increase in volume took precedence over the decrease in pressure. But is that likely to happen?
 
You will get experimental variation due to lots of things - including variations in the composition of the balloons. It is just not the same each time. You'd expect so many random variations to produce a normal distribution in your results ... which is why mean and standard deviation are important. If "no change" is within 2sd of the mean change then your results are consistent with no change in temperature. (If there were any change, you failed to measure it.)

BTW: did you measure the pressure inside the balloon?

If our results are correct, then I suppose the increase in volume took precedence over the decrease in pressure. But is that likely to happen?
Well that is the question isn't it? So think of the different thermodynamic processes and ask which one you'd expect to be dominant. Should have done this before the experiment... it is seldom meaningful to confirm a theory after the fact.

Note: experimental results are always "correct". They are what you measured.
 
Do not forget the elastic wall of the balloon. While the gas extends through the hole into the external atmosphere and does work against the external pressure, the walls move inward, pressing the gas out. This is work done on the gas, warming it up, while the extension of the gas results in cooling down.

ehild
 

Similar threads

Replies
5
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 16 ·
Replies
16
Views
3K
Replies
24
Views
3K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
18
Views
7K
Replies
11
Views
5K
Replies
17
Views
3K
Replies
5
Views
1K
  • · Replies 5 ·
Replies
5
Views
1K