A Does a DC supplied wavy superconductor give off EM radiation?

AI Thread Summary
A superconductor flowing a direct current (DC) does not emit electromagnetic radiation under stable conditions. While initiating the current creates a transient magnetic field, this does not lead to continuous radiation. The magnetic field remains stable as long as the DC is maintained, with no changing dipole moments to produce radiation. Terminating the current causes the magnetic field to return to zero, but again, no radiation is emitted during the steady state. Therefore, regardless of the superconductor's shape, DC does not result in electromagnetic radiation.
binis
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A superconductor has the shape of a uniform plane wave. If it is flowed by a direct current,
is it emitting electromagnetic radiation or not?
 
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When the current is initiated, a magnetic field is radiated due to the turn-on transient.

A continuous direct current maintains a stable magnetic field, being the vector sum of all the magnetic fields from all the segments of the circuit.

When the current is terminated, the radiated magnetic field will fall back to zero.
 
binis said:
If it is flowed by a direct current,
is it emitting electromagnetic radiation or not?
No. The shape of the loop is irrelevant. When it is DC there is no radiation.

binis said:
have a look to this post
Have a look at the rest of that thread. The post you mention was subsequently corrected, and since you participated there you are already aware.

What produces radiation is a changing dipole moment (or higher-order multipole). A single accelerating charge does not produce radiation because of acceleration. It produces radiation because of a changing dipole moment.

A DC current has no changing moments, so no radiation, regardless of the shape of the loop.
 
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