Does a DC supplied wavy superconductor give off EM radiation?

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SUMMARY

A direct current (DC) supplied to a superconductor does not emit electromagnetic radiation, regardless of the shape of the superconductor. The discussion clarifies that while a magnetic field is generated during the turn-on transient of the current, a continuous DC maintains a stable magnetic field without producing radiation. The key factor for radiation is a changing dipole moment, which does not occur in a steady DC scenario.

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binis
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A superconductor has the shape of a uniform plane wave. If it is flowed by a direct current,
is it emitting electromagnetic radiation or not?
 
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When the current is initiated, a magnetic field is radiated due to the turn-on transient.

A continuous direct current maintains a stable magnetic field, being the vector sum of all the magnetic fields from all the segments of the circuit.

When the current is terminated, the radiated magnetic field will fall back to zero.
 
binis said:
If it is flowed by a direct current,
is it emitting electromagnetic radiation or not?
No. The shape of the loop is irrelevant. When it is DC there is no radiation.

binis said:
have a look to this post
Have a look at the rest of that thread. The post you mention was subsequently corrected, and since you participated there you are already aware.

What produces radiation is a changing dipole moment (or higher-order multipole). A single accelerating charge does not produce radiation because of acceleration. It produces radiation because of a changing dipole moment.

A DC current has no changing moments, so no radiation, regardless of the shape of the loop.
 
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