Does diagonalizable imply symmetric?

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SUMMARY

The discussion centers on the relationship between diagonalizable matrices and symmetric matrices in the context of proving the well-posedness of a partial differential equation (PDE) system. The participant asserts that diagonalizability with real eigenvalues does not necessarily imply symmetry, referencing a specific counterexample: the matrix (1 2; 0 3). The conversation highlights the need for additional theorems or methods to establish the well-posedness of the PDE system.

PREREQUISITES
  • Understanding of matrix diagonalization
  • Knowledge of eigenvalues and eigenvectors
  • Familiarity with symmetric matrices
  • Basic concepts of partial differential equations (PDEs)
NEXT STEPS
  • Research theorems relating orthogonally diagonalizable matrices to symmetric matrices
  • Explore methods for proving well-posedness in PDE systems
  • Study counterexamples in linear algebra to understand matrix properties
  • Investigate the implications of real eigenvalues on matrix characteristics
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Mathematicians, students studying linear algebra, and researchers working on partial differential equations will benefit from this discussion.

Scootertaj
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In order to prove my PDE system is well-posed, I need to show that if a matrix is diagonalizable and has only real eigenvalues, then it's symmetric.



Homework Equations


I've found theorems that relate orthogonally diagonalizable and symmetric matrices, but is that sufficient?


The Attempt at a Solution


See above.
 
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It's not true. Consider the matrix

\left(\begin{array}{cc} 1 & 2\\ 0 & 3\end{array}\right)
 
Darn.. well I guess to find another way to show the PDE is well-posed.
 

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