Does Earth's Gravity Do Work on Satellites?

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SUMMARY

The discussion confirms that Earth's gravity does not perform work on satellites in a perfect circular orbit. The fundamental definition of work, W = ∫ F * ds, indicates that since the gravitational force vector is always perpendicular to the displacement vector in circular motion, the work done is zero. Consequently, both potential and kinetic energy remain constant, reinforcing that no work is done by gravity on orbiting satellites.

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putongren
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Does the gravity of Earth do any work on satellites orbiting the planet, assuming perfect circular orbit?

General Definition of work: W=(line integral) F * ds , F=force vector, ds=infinitesimal displacement vector, *=dot product.

We know that in circular motion, the velocity vector is always perpendicular to the centripetal acceleration (I think we assume that centripetal acceleration is equated to gravitational acceleration), so 0 = F * v for all positions. so that means that 0 = F * ds/dt. If F * ds =0 for all positions, then W = 0. Does 0 = F * ds/dt imply F * ds = 0?

Thank you.
 
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Correct.
 
putongren said:
Does the gravity of Earth do any work on satellites orbiting the planet, assuming perfect circular orbit?
Perfect circular orbit means: potential energy doesn't change and kinetic energy doesn't change so there is no work to do.
 

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