Does expression equal 0 when value approaches 0?

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The discussion centers on the evaluation of limits in calculus, specifically addressing the expression $\lim_{{z}\to{q}} z \ln(z) f(z)$. It concludes that if $\lim_{{z}\to{q}} f(z) = 0$, it does not guarantee that $\lim_{{z}\to{q}} z \ln(z) f(z)$ equals 0 due to the presence of indeterminate forms such as $0 \times \infty$. For the limit to be evaluated as a product of limits, both individual limits must exist. This highlights the importance of understanding the conditions under which limits can be separated in calculus.

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If anyone value in an expression is approaching 0, does the entire expression equal 0?

So for example, for the limit $\lim_{{z}\to{q}} z ln(z) f(z)$. If $\lim_{{z}\to{q}}f(z) = 0$, then does $\lim_{{z}\to{q}} z ln(z) f(z)$ equal 0?
 
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Not necessarily. There is (at least) the indeterminate form $0\times\infty$ to consider.
 
Yes, suppose we have:

$$L=\lim_{x\to a}\left(f(x)\cdot g(x)\right)$$

Now, in order to write:

$$L=\lim_{x\to a}\left(f(x)\right)\cdot\lim_{x\to a}\left(g(x)\right)$$

We require that both $$\lim_{x\to a}\left(f(x)\right)$$ and $$\lim_{x\to a}\left(g(x)\right)$$ exist.
 

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