Does f(x) Approach Zero as x Approaches Infinity?

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Math_Frank
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Homework Statement



Given the odd integral

[tex]\int_{a}^{b} f(x) dx[/tex] How do I prove that

f(x) -> 0 for [tex]x \to \infty[/tex]??

The Attempt at a Solution



Is it? For the above to be true, then there exist an [tex]\epsilon > 0[/tex] such that

[tex]|\int_{a}^{b} f(x) dx-0| \leq \epsilon[/tex]?

I am stuck here!

Am I going the right way?

Sincerely
Frank
 
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What you've written doesn't really make sense. What is this question from and about?
 
NateTG said:
What you've written doesn't really make sense. What is this question from and about?

The Question is

Given the integeral

[tex]f(t) = \int_{t}^{2t} e^{-x^2} dx[/tex] then prove that if [tex]f(x) \to 0[/tex] then

[tex]n \to \infty[/tex]

Isn't that convergens or it simply existence of the limit?
 
Math_Frank said:
The Question is

Given the integeral

[tex]f(t) = \int_{t}^{2t} e^{-x^2} dx[/tex] then prove that if [tex]f(x) \to 0[/tex] then

[tex]n \to \infty[/tex]

Isn't that convergens or it simply existence of the limit?

Where does [itex]n[/itex] come from?

Do you mean "[itex]\lim_{x \rightarrow \infty} f(x)=0[/itex]" when you write "[itex]f(x) \to 0[/itex]"
 
NateTG said:
Where does [itex]n[/itex] come from?

Do you mean "[itex]\lim_{x \rightarrow \infty} f(x)=0[/itex]" when you write "[itex]f(x) \to 0[/itex]"

Yes.
 
You need to show both existence and convergence of the limit.