Does Increasing Torque Affect Kinetic Friction When a Wheel Slips?

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Homework Help Overview

The discussion revolves around the relationship between torque and kinetic friction in the context of a slipping wheel. Participants explore whether increasing torque affects the force of kinetic friction acting on the wheel.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to analyze the independence of translational acceleration from torque during slipping, suggesting that kinetic friction remains constant regardless of torque. Other participants engage by confirming this perspective and discussing the distinction between static and kinetic friction.

Discussion Status

The discussion is active, with participants providing insights and affirmations regarding the original poster's reasoning. There is a recognition of the complexity of friction models, particularly in distinguishing between static and kinetic friction.

Contextual Notes

Participants reference the coefficient of kinetic friction and the normal force, indicating that these factors are central to the discussion. The original poster's intuition about the relationship between torque and friction is acknowledged, suggesting a deeper exploration of assumptions related to frictional forces.

Just a nobody
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This isn't actually a homework question, but the style of it fits best in this forum.

Diagram
http://img355.imageshack.us/img355/9836/text5029jb0.png
  • [tex]\tau[/tex] - torque of wheel
  • [tex]R[/tex] - radius of wheel
  • [tex]f_k[/tex] - force due to kinetic friction

Question
Is the translational acceleration of the wheel independent of the torque when the wheel is slipping? That is, if the torque is increased, will [tex]f_k[/tex] increase?

My attempt (Not necessarily correct)

Additional variables:
  • [tex]u_k[/tex] - coefficient of kinetic friction between floor and wheel
  • [tex]N[/tex] - normal force
  • [tex]m[/tex] - mass of wheel
  • [tex]g[/tex] - acceleration due to gravity

[tex]N = mg[/tex] (since it's on a flat surface)
[tex]f_k = u_k N = u_k m g[/tex]

[tex]\tau[/tex] does not appear in the equation, so [tex]f_k[/tex] is independent of torque. No matter how much the torque is increased, [tex]f_k[/tex] will not increase if the wheel slips.

Thanks for reading through my question,
David
 
Last edited by a moderator:
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Well, sure. If the frictional force is purely due to kinetic friction, it's only dependent on the normal force and independent of torque.
 
Okay, thank you very much for answering. My intuition told me otherwise, so I wanted to verify my answer.
 
Your intuition probably told you otherwise because if the wheel is not slipping then you are dealing with static friction which is very dependent on the applied force. Even if it is slipping kinetic friction is only an approximate model. Don't dis your intuition too much.
 
Last edited:

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