Does inviscid mean shear stress is negligible?

  • Thread starter corona7w
  • Start date
  • #1
11
0

Main Question or Discussion Point

I have this flow with Reynold's number in the 10^5, which I think it's big enough to treat the fluid as inviscid, does this also mean I can assume the shear stress is negligible?
 

Answers and Replies

  • #2
2,985
13
First, what does inviscid mean, by definition?

Second, just because the flow is 10^5 does not mean you can ignore shear stress. What is the object under consideration?
 
  • #3
11
0
It's a sphere with radius R immersed in water of velocity V. I'm asked to calculate the drag on it. I know the formula for drag is integral of Pcos theta dA + integral of shear stress sin theta dA . And I am not given any information regarding the shear stress, so I thought since the Re is pretty big, we might just treat the shear stress as negligible so only the first term of the equation needs to be calculated.
 
  • #4
1,564
6
You could assume inviscid flow but its probably not an accurate assumption. Whats the viscosity or what fluid are you using?
 
Last edited:
  • #5
13
0
I have this flow with Reynold's number in the 10^5, which I think it's big enough to treat the fluid as inviscid, does this also mean I can assume the shear stress is negligible?
If u are talking about term "Inviscid"....then u are correct.. its means flow is non viscous ,,,that in return means SHEAR STRESSES are minimum and can be neglected
 

Related Threads for: Does inviscid mean shear stress is negligible?

Replies
2
Views
1K
  • Last Post
Replies
2
Views
2K
  • Last Post
Replies
3
Views
3K
  • Last Post
Replies
6
Views
3K
Replies
2
Views
619
  • Last Post
Replies
1
Views
4K
  • Last Post
Replies
9
Views
5K
  • Last Post
Replies
1
Views
464
Top