Does Kinetic Energy Apply to Bullets in Ballistics?

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SUMMARY

Kinetic energy applies to bullets in ballistics, as they possess both mass and velocity. The formula for kinetic energy, K = 1/2 * m * v^2, is relevant for calculating the energy of a bullet in motion. There is a distinction between translational kinetic energy and rotational kinetic energy; bullets can exhibit both types due to their motion and rotation. Understanding these concepts is crucial for comprehending the physics of projectile motion.

PREREQUISITES
  • Understanding of classical mechanics
  • Familiarity with the kinetic energy formula K = 1/2 * m * v^2
  • Knowledge of translational and rotational motion
  • Basic principles of ballistics
NEXT STEPS
  • Research the differences between translational and rotational kinetic energy
  • Explore the principles of projectile motion in ballistics
  • Learn about the effects of air resistance on bullet trajectory
  • Study the impact of bullet mass and velocity on kinetic energy calculations
USEFUL FOR

Students studying physics, ballistics experts, and anyone interested in the mechanics of projectile motion and energy calculations.

Guapa
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Homework Statement


Just a simple question, does Kinnetic energy applies to a bullet that has being shot?

Homework Equations


K=1/2 * m * v^2

The Attempt at a Solution


N/A
 
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What are your thoughts on the matter? Does the bullet have mass? Does it have velocity?
 
Yes it has mass, and it has velocity.
I was reading about Kinetic energy not applies to rotating objects so then I thought it does not apply to flying rotating objects, therefore it does not apply to bullets traveling on our space.
 
Guapa said:
Yes it has mass, and it has velocity.
I was reading about Kinetic energy not applies to rotating objects so then I thought it does not apply to flying rotating objects, therefore it does not apply to bullets traveling on our space.
There is a distinction between translational kinetic energy and rotational kinetic energy. Perhaps that is what you read about? An object can have both if it is both translating (moving) and rotating.
 
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Now that enlighten me, I just scanned through the initial part of this article and did not went through all, I got a bit disturbed by the initial statement:
In classical mechanics, the kinetic energy of a non-rotating object of massm traveling at a speedv is $$ \frac {1}{2} \cdot m \cdot v^2 $$ . From wikipedia.
This is what little knowledge does to me o:), complete embarrassment.
Thank you Sir.:biggrin:
 

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