I know this is a very newbie question but I'm a newbie when it comes to the mathematics involved in GR. My question is if gravity is the curvature of space-time then would an observer on a larger gravity source, such as Jupiter actually experience more gravity? Since space-time itself is compressed wouldn't Jupiter be much larger to a local observer than we have measured since they are also compressed more by space-time? I would think this would mean the gravity experienced by the observer would end up the same since their space-time compressed self would see a smaller portion of the gravity due to the fact that the observer and gravity source are both space-time compressed. I don't yet have the mathematical skills to try to do calculations on tensors to answer this question myself. I don't think lower "weight" experienced on the moon is good enough proof for this since a portion of the gravity of the moon is actually canceled, on the light side of the moon, by the gravity of the earth.(adsbygoogle = window.adsbygoogle || []).push({});

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# Does observer's sense of gravity change?

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