Does Speed Increase for Dropped Objects Based on Height?

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SUMMARY

The discussion clarifies that when two objects are dropped from different heights, their velocities differ at specific points during their fall. Object A, dropped from 2 meters, reaches a velocity of 4.4 m/s after falling 1 meter, while Object B, released from 1 meter after Object A has fallen, starts with an initial velocity of 0 m/s. The relationship governing this scenario is defined by the equation V_f^2 = V_i^2 - 2ad, where a equals -9.8 m/s². Thus, the speed of an object increases with the distance it falls until it reaches terminal velocity.

PREREQUISITES
  • Understanding of basic physics concepts, particularly kinematics.
  • Familiarity with the equations of motion, specifically V_f^2 = V_i^2 - 2ad.
  • Knowledge of gravitational acceleration, specifically -9.8 m/s².
  • Concept of terminal velocity in free fall.
NEXT STEPS
  • Study the principles of kinematics in greater detail, focusing on free fall and acceleration.
  • Explore the concept of terminal velocity and its implications in physics.
  • Learn about the effects of air resistance on falling objects.
  • Investigate real-world applications of these principles in engineering and physics experiments.
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This discussion is beneficial for physics students, educators, and anyone interested in understanding the dynamics of falling objects and the principles of motion.

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I'm relatively new to physics.

I know that dropping 2 objects, at the distance from the ground, they will land at the same time.

But what would happen if you dropped objectA at 2 meters height, and held objectB at one meter height, and only let go of objectB, when ObjectA has already fallen 1m. Will they fall at the same time?

basically what I am asking is, does the speed of an object build up, the further it falls?
 
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No, because for object B, the initial velocity is 0, and for object A, the initial velocity when it gets to the location of object B is 4.4 m/s.

The relationship between final velocity, initial velocity, displacement, and acceleration is

[tex]V_f^2=V_i^2-2ad[/tex] where a = -9.8 m/s^2

So yes, the velocity builds up the further or longer you fall until you reach terminal velocity.
 
Last edited:
thanks, that cleared it up.
 

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