Does squaring velocity eliminate negative signs in v²=v₀²+2aΔx?

[ZenOne]

When using the equation v^2=V0^2 + 2a (x)...

If V or V0 is negative, does it become positive after squaring? (Basically, is the negative sign in the bracket or outside)?

Thanks in advance.

 

[Vagn]

The velocities will be positive when squared.

 

[Doc Al]

If V or V0 is negative, does it become positive after squaring?

V^2 and V0^2 will be positive quantities even when V or V0 is negative.