Does the Charge on NOS Affect the Charge on Fe?

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Discussion Overview

The discussion revolves around the charge states of iron in coordination compounds, specifically in the reaction between sodium sulfide and iron cyanide complexes. Participants explore the oxidation states of iron and the charge on the NOS ligand, seeking clarity on how these factors influence each other.

Discussion Character

  • Homework-related
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant states that in the reaction, iron is initially in the +2 oxidation state and questions whether it becomes +3 after the reaction, depending on the charge of NOS.
  • Another participant proposes that the net charge of [Fe(CN)5(NO)] is -2 and that of [Fe(CN)5(NOS)] is -4, suggesting that iron could be in a +4 state during the reaction.
  • A participant challenges the introduction of +4 as a stable state for iron, emphasizing that iron typically exists in +2 and +3 states.
  • There is a mention of iron having multiple oxidation states, with a reference to a source that lists these states, indicating that the oxidation states can vary based on the compound and structure.
  • Participants discuss the octahedral geometry of the coordination compounds and the implications for charge calculations.

Areas of Agreement / Disagreement

Participants express differing views on the oxidation states of iron and the charge on the NOS ligand. There is no consensus on whether iron can exist in a +4 state or what the charge on NOS is, leaving the discussion unresolved.

Contextual Notes

There are unresolved assumptions regarding the oxidation states of iron and the charge on NOS, as well as the implications of octahedral geometry on charge calculations.

mooncrater
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Homework Statement


There is a reaction given in my textbook which says:
##Na_2S+Na_2 [Fe(CN)_5 (NO)]## ## \longrightarrow## ## Na_4 [Fe (CN)_5 (NOS)]##
I know initially Fe is in +2 state.
But does it become +3 charged after the reaction? What is the charge on NOS? Is it ##NOS^{-1}## or ##NOS^{-2}##?

Homework Equations

The Attempt at a Solution


I don't know... charge on ##Fe## depends upon the charge on ##NOS##... which I don't know.
Any help appreciated.
 
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I don't know how much I can help without getting castigated by admin, but I will risk it... The [Fe(CN)5(NO)] = -2 net charge and [Fe(CN)5(NOS)] = -4 net charge. Both are octahedral coordination structures with Fe+4 + 2e- => Fe+2 as the reduction and sulfur in Na2S is -2 charge being oxidized to So in the -NOS structure. Both -NO and -NOS have the same oxidation states = -1. Look up octahedral geometry, place CN (= -1 charge) on all points in the plane and one above the plane. The -NO and - NOS are each below the plane. With all the points -1 = -6 and Fe+4 in the reactant side = net -2 for the reactant anion. Draw the same structure with all points -CN and one -NOS => -6 again on the product side, but Fe in the product structure is +2. Then [(-6) + (+2)] = -4 for the product anion structure. Hope I don't get fussed at. Good luck.
 
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Thanks for your reply. I had some doubts:
##Fe## has two stable states... ##Fe^{+2}## and ##Fe^{+3}##. From where ##Fe^{+4}## came? Originally the compound has ##Fe^{+2}##.
 
mooncrater said:
Thanks for your reply. I had some doubts:
##Fe## has two stable states... ##Fe^{+2}## and ##Fe^{+3}##. From where ##Fe^{+4}## came? Originally the compound has ##Fe^{+2}##.
+2 and +3 oxidation states for iron are the most common, but actually, iron can have eight (8) oxidation states depending on the compound and structure it is associated with... Here's a link that may help on this... http://en.wikipedia.org/wiki/Iron ... Scroll down to 'Atomic Properties', there will be a list of the possible oxidation states for iron.

Did you look up the octahedral geometry for coordination compounds? Follow my suggestion about placing the substrates as suggested, then check the net charges.
 
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Here's Iron in an Octahedral Geometry for FeCl3-. The [Fe(CN)5(NO)]2- and [Fe(CN)5(NOS)]4- follow the same configurations.
upload_2015-5-13_0-52-16.png
 
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mooncrater said:

Homework Statement


There is a reaction given in my textbook which says:
##Na_2S+Na_2 [Fe(CN)_5 (NO)]## ## \longrightarrow## ## Na_4 [Fe (CN)_5 (NOS)]##
I know initially Fe is in +2 state.
But does it become +3 charged after the reaction? What is the charge on NOS? Is it ##NOS^{-1}## or ##NOS^{-2}##?

Homework Equations

The Attempt at a Solution


I don't know... charge on ##Fe## depends upon the charge on ##NOS##... which I don't know.
Any help appreciated.
Hey guy, how you doing on the problem? Just checking if all is OK. Hope I've helped. jp
 

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