Does the comparison test work for this series inequality?

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Square1
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Hey check out the attached picture. I think I solved the issue now but just to confirm perhaps...

If I were to continue here using the comparison test, is the only problem that b-subn limit equals 0, so the comparison test is inconclusive?

Otherwise, since our summation does not included n=0 (or other undefined values right?), my simplified form of a-subn holds, and my inequality is correct?

Thanks for any help.
 
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  • Handwritten notes on lined paper: the series sum from n=1 to infinity of (n + sqrt(n))/(n + n^2), asking whether it converges or diverges. Below, a comparison test section factors n out of the fraction to give a_n = (1 + 1/sqrt(n))/(1 + n), and sets b_n = (1 + 1/sqrt(n))/n, noting the limit of b_n as n approaches infinity is 0.
    series pic.jpg
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Your picture is hard to read. However, it seems you have a series where for large n, the terms are approximately 1/n, so the series diverges.