Does the derivative of a P(V) eqn give the eqn for change in Pressure?

[JoeyBob]

Homework Statement

N/A

Relevant Equations

N/A

I know the integral of a P(V) eqn gives an eqn for work.

I was wondering if taking the derivative of a P(V) eqn gives an eqn for change in pressure?

 

[Chestermiller]

Homework Statement:: N/A
Relevant Equations:: N/A

I know the integral of a P(V) eqn gives an eqn for work.

I was wondering if taking the derivative of a P(V) eqn gives an eqn for change in pressure?

What is your definition of an "equation for change in pressure?"

 

[JoeyBob]

What is your definition of an "equation for change in pressure?"

Gives rate of change.

For instance, if you take the derivative of velocity, you get acceleration, which is the rate of change of velocity.

 

[Orodruin]

For instance, if you take the derivative of velocity, you get acceleration, which is the rate of change of velocity.

No, the derivative of velocity with respect to time is acceleration. What you differentiate with respect to is important. For example, there are situations where velocity is given as a function of position. The derivative of such a velocity function is not acceleration.

Derivatives are rates of change with respect to the differentiation variable, but depending on what the differentiation variable is, the interpretation may vary.

 

[JoeyBob]

No, the derivative of velocity with respect to time is acceleration. What you differentiate with respect to is important. For example, there are situations where velocity is given as a function of position. The derivative of such a velocity function is not acceleration.

Derivatives are rates of change with respect to the differentiation variable, but depending on what the differentiation variable is, the interpretation may vary.

So it would be rate of change with respect to volume?