Does the electric field reach a value equal to half its maximum value?

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SUMMARY

The electric field of a non-conducting sphere with a radius of R = 7 cm and a uniformly distributed charge of Q = 4 mC reaches half its maximum value at two distinct radii. The maximum electric field (Emax) can be determined using Gauss' Law, which is essential for accurately calculating the electric field as a function of radius. The initial calculation of 3.5 cm is incorrect, as it does not utilize the proper formula for electric fields. The correct approach involves solving for the radius where the electric field equals half of Emax.

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A non-conducting sphere of radius R = 7 cm carries a charge Q = 4 mC distributed uniformly throughout its volume. At what distance, measured from the center of the sphere does the electric field reach a value equal to half its maximum value?

My attempt:

Emax= q(4mC)/7
r= 7/2 cm = 3.5

is this correct? because one of my friend said 9.9... so idk if I am right or are both values
 
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I'm not sure how exactly you determined the maximum of the electric field. It appears that all you did was divide the charge by the radius. This is not a correct formula and doesn't even give you the units of an electric field. My suggestion would be to use Gauss' Law to find the electric field as a function of radius. This will allow you to determine at what radius the maximum occurs (although with a bit of experience it should be fairly obvious). From there you can set the equation for the field equal to half that value and solve for r.

Just a hint, there should actually be two radii at which the field is equal to half its maximum.
 
Last edited:
I agree with your friend.
 

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