Does the inverse distribute over the group operation o?

  • Thread starter Thread starter aeonstrife
  • Start date Start date
  • Tags Tags
    Group Set
Click For Summary
SUMMARY

The discussion centers on the group G defined with respect to the operation o and the newly defined operation #, where x#y=(xoy)^-1. It is established that while the operation # is closed, G does not form a group under this operation due to the failure of associativity. The key question raised is whether the inverse distributes over the group operation o, specifically if (xoy)^-1 equals x^-1oy^-1, which is critical for proving the group properties under #.

PREREQUISITES
  • Understanding of group theory concepts, specifically group operations and inverses.
  • Familiarity with the definition of a group and its properties, including closure and associativity.
  • Knowledge of the notation and operations involving inverses in algebraic structures.
  • Basic comprehension of how to manipulate algebraic expressions involving group operations.
NEXT STEPS
  • Research the properties of group operations and the implications of associativity in group theory.
  • Study the concept of inverses in algebraic structures and their behavior under different operations.
  • Explore examples of non-group structures to understand the limitations of operations like #.
  • Learn about the implications of the failure of distributive properties in group operations.
USEFUL FOR

This discussion is beneficial for mathematicians, students of abstract algebra, and anyone studying group theory, particularly those interested in the properties of operations and inverses within algebraic structures.

aeonstrife
Messages
2
Reaction score
0
G is a group with respect to o.

Another operation # is defined by x#y=(xoy)^-1

Show that G is not a group wrt #

I've gotten that the operation is closed but I can't figure out how to prove associativity because the inverse is a bit confusing.
 
Physics news on Phys.org
How else can you write (xoy)-1?
 
o is an operation. (xoy)^-1 is just the inverse of (xoy) if that makes sense
 
I think what office shredder was asking is "Does the inverse distribute over the group operation o?" In other words, does (xoy)-1 = x-1oy-1 or does it equal something else?
 

Similar threads

Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 26 ·
Replies
26
Views
965
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K