Is the Direct Product of Groups Associative and Have an Identity Element?

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SUMMARY

The discussion focuses on proving the axioms of the direct product of groups, specifically associativity, the existence of an identity element, and the existence of right inverses. It is established that the direct product of groups G and H is associative due to the associative nature of their binary operations. The identity element of the direct product is correctly identified as the pair (e, f), where e and f are the identity elements of groups G and H, respectively. The challenge of finding right inverses is acknowledged, emphasizing that knowledge of the binary operations is not necessary to prove the existence of inverses in the direct product.

PREREQUISITES
  • Understanding of group theory concepts, including groups, binary operations, and axioms.
  • Familiarity with the definitions of identity elements and inverses in group theory.
  • Knowledge of the direct product of groups and its properties.
  • Basic mathematical proof techniques for validating group properties.
NEXT STEPS
  • Study the properties of direct products in group theory.
  • Learn how to construct and prove the existence of inverses in direct products.
  • Explore examples of direct products with specific groups, such as cyclic groups.
  • Investigate the implications of associativity in more complex group structures.
USEFUL FOR

Mathematicians, students of abstract algebra, and anyone interested in understanding the foundational properties of group theory and the direct product of groups.

joelkato1605
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Homework Statement
Prove G X H is a group.
Relevant Equations
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So I that I need to prove the axioms: associativity, existence of the identity element, and existence of the right inverse.

For associativity I know that the binary operations of G and H have to already be associative, and the elements of G X H are made up of these binary operations, so therefore it is associative?

For identity element let G have identity element e, and H have identity element f, can the identity element of G X H have the set (e,f), so that if (x,y) are included in G X H then (e,f) * (x,y) = (x,y) = (x,y) * (e,f)?

For the right inverse I am stuck, I don't know how to find it without knowing what the binary operations actually do.
 

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Remember that G and H are groups, so you know that they each have an identity element and inverses for their respective operations. That should be enough. You don't need to know anything more about them.
 
joelkato1605 said:
For associativity I know that the binary operations of G and H have to already be associative, and the elements of G X H are made up of these binary operations, so therefore it is associative?

I think you might know what you're trying to say, but the words here are wrong. The elements of GxH are not made up of the binary operations on G and H, they are made from elements of G and H.

I think it is a good exercise to actually write down (ab)c and show how it transforms into a(bc) step by step.
 
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