Does the number of turns on a loop affect the current or magnetic field?

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Homework Help Overview

The discussion revolves around the relationship between the number of turns on a loop and its effect on current and magnetic field, specifically in the context of electromagnetic theory.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore whether increasing the number of turns on a coil affects the magnetic field or current, with some questioning the underlying reasons for any changes observed.

Discussion Status

Participants are actively engaging with the concepts, with some providing insights into the effects of self-inductance and magnetic flux. There is a recognition of the complexity of the problem, and multiple interpretations regarding the relationship between turns, current, and magnetic field are being discussed.

Contextual Notes

There is mention of fixed current and the implications of self-inductance, indicating that assumptions about the system's constraints are being examined.

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Homework Statement


Do the number of turns on the loop magnify the current or the magnetic field?

Homework Equations


The Attempt at a Solution


I believe its a magnetic field, but can someone confirm this?

Thanks for any replies.
 
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If a fixed current I is passed through the coil, the magnetic field would be \munI.

But due to self inductance, the current in the coil changes. As you would already know, self inductance depends on the no. of turns in the coil.
 
Thanks for the reply.

So, because of the turns on the coil, the magnetic field increases, but does the magnetic field increase because the current in the conductor creating the magnetic field increases? Or is there another reason for the change in magnetic field?
 
This is a poorly defined problem. Assuming you have a loop of wire with N turns. What happens with a fixed current if you add more turns?

Each turn adds more flux down the axis of the loop. The current doesn't change because it's fixed.

If you are talking about inductance, that goes up as the square of the number of turns.

If you are talking about the current through an inductor it is equal to the time integral of the applied voltage divided by the inductance.
 

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