I know that the example I use has been done online many times, but my question isn't about how to get the answer, that is obvious, my question goes a little deeper.(adsbygoogle = window.adsbygoogle || []).push({});

For example when deriving the equation for an ellipse we have the constraint that the ellipse equation describe the set of (x,y) such that the sum of the distances from (x,y) to the foci [(-c,0), (c,0)] is constant, lets say 2a for convenience.

After setting up the equality that c^2+b^2=a^2 (Where b is the y value when (x,y) is in between the foci) we quickly establish the following equation which is used in various derivations online:

sqrt((x+c)^2+y^2)+sqrt((x-c)^2+y^2)=2a

If we square both sides first and then isolate and simplify we arrive at an impasse:

2x^2+2y^2+2c^2+2*sqrt(c^4-2c^2(x^2-y^2)+(x^2-y^2)^2)=4a^2

But if we isolate one of the radicals first and then square we can simplify down to an expression

cx-a^2=a*sqrt((x-c)^2+y^2)

And then if we square both sides again and simplify we can get an expression that allows us to use the c^2+b^2=a^2 relation and obtain the formula.

I'm confused as to why one sequence of steps (squaring, isolating, simplifying,...) does not allow you to find the solution whereas another set of steps (isolating, squaring, simplifying, squaring,...) does allow you to find the solution. It seems to me that since any of the expressions along the way to finding the solution are transformable into each other by simple techniques (adding 0, multiplying by 1, isolating, squaring, etc.) that any path should allow us to arrive at the solution. Now maybe my algebra is rusty and maybe you're supposed to always isolate first, but I'm not sure. Can someone help explain this to me?

**Physics Forums - The Fusion of Science and Community**

# Does the order of algebraic steps (not operations) matter?

Know someone interested in this topic? Share a link to this question via email,
Google+,
Twitter, or
Facebook

- Similar discussions for: Does the order of algebraic steps (not operations) matter?

Loading...

**Physics Forums - The Fusion of Science and Community**