MHB Does the Sequence Converge or Diverge?

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SUMMARY

The sequence defined by \( a_n = \frac{(-1)^n n^3}{n^3 + 2n^2 + 1} \) diverges due to its oscillatory behavior. Although the limit of the modified sequence \( \frac{1}{1 + \frac{2}{n} + \frac{1}{n^3}} \) approaches 1 as \( n \) approaches infinity, the presence of the term \( (-1)^n \) causes \( a_n \) to oscillate between values close to -1 and 1. Therefore, the sequence does not converge to a single limit.

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$\tiny{s4.11.1.26} \\$
$\text{ Determine whether the sequence converges or diverges. If it converges, find the limit.} \\$
$$\displaystyle a_n=\frac{(-1)^n n^3}{n^3+2n^2+1}$$
$\text{ divide every term by $n^3$}$
$$\displaystyle a_n=\frac{(-1)^n }{1+\frac{2}{n}+\frac{1}{n^3}}$$
$\text{ take the limit}$
$$\displaystyle \lim_{{n}\to{\infty}} a_n=1$$
$\text{suggestions?}$
☕
 
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The limit of $a_n$ is not 1. If we replace $(-1)^n$ with 1, then indeed the limit is 1. But as it is, $a_n$ oscillate between numbers that are close to $-1$ and those that are close to $1$.
 
so it diverges
 
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