MHB Does the Sequence Converge or Diverge?

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The sequence defined by \( a_n = \frac{(-1)^n n^3}{n^3 + 2n^2 + 1} \) diverges due to its oscillating nature. Dividing each term by \( n^3 \) leads to the simplified form \( a_n = \frac{(-1)^n}{1 + \frac{2}{n} + \frac{1}{n^3}} \). As \( n \) approaches infinity, the limit does not stabilize at a single value; instead, it oscillates between values near -1 and 1. Therefore, the sequence does not converge. The conclusion is that the sequence diverges.
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$\tiny{s4.11.1.26} \\$
$\text{ Determine whether the sequence converges or diverges. If it converges, find the limit.} \\$
$$\displaystyle a_n=\frac{(-1)^n n^3}{n^3+2n^2+1}$$
$\text{ divide every term by $n^3$}$
$$\displaystyle a_n=\frac{(-1)^n }{1+\frac{2}{n}+\frac{1}{n^3}}$$
$\text{ take the limit}$
$$\displaystyle \lim_{{n}\to{\infty}} a_n=1$$
$\text{suggestions?}$
☕
 
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The limit of $a_n$ is not 1. If we replace $(-1)^n$ with 1, then indeed the limit is 1. But as it is, $a_n$ oscillate between numbers that are close to $-1$ and those that are close to $1$.
 
so it diverges
 

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