Does the series converge or diverge?

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Homework Statement


Let [tex]x_{n}[/tex] be a monotone increasing sequence such that [tex]x_{n+1}-x_{n}< \frac{1}{n}.[/tex] Must [tex]x_{n}[/tex] converge ?

Homework Equations



Instinctively, I think it converges since the terms "bunch" up as n increases.

The Attempt at a Solution


[tex]|x_{n+1}-L| \leq |x_{n+1}-x_{n}| + |x_{n}-L|[/tex].
[tex]|x_{n+1}-L|< \frac{1}{n}+ |x_{n}-L|[/tex] . But this doesn't tell me anything about convergence.

If I apply the triangle inequality continuosly all I can see is that
[tex]|x_{n+1}-L|< \sum\frac{1}{n}[/tex]

What can you guys tell me ?
 
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Great that makes sense. I had a feeling it need not converge but I was unsure. Does this work too...
Define a sequence such that [tex]x_{n}-x_{n-1}= \frac{1}{n}[/tex] such that the sequence has positive terms them
[tex]|x_{n} -L| =|1 + 1/2 + ...+ 1/n|[/tex ] which does not converge.<br /> I suppose that also works correct? <br /> Excuse my latex, typing from a phone is difficult.[/tex]
 
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Yes, that works.
 
Thanks a lot for the help.
 
So what have you decided, does it converges or diverges? :)