Does this Series Converge or Diverge, by which test(s)?

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Homework Help Overview

The discussion revolves around the convergence or divergence of the series Ʃ (2n)!/(n-1)*3^n, starting from n=2 to infinity. Participants are exploring the application of convergence tests, particularly the ratio test and nth-term test.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants have attempted the ratio test and nth-term test, noting that the results lead to infinity. There is uncertainty regarding the implications of this outcome for convergence.

Discussion Status

Some participants have provided guidance on interpreting the results of the ratio test, specifically regarding the condition when L>1. However, there appears to be some confusion about the correct interpretation of the limit in relation to convergence and divergence.

Contextual Notes

There is a repeated emphasis on the limit obtained from the ratio test and its implications, indicating a potential misunderstanding of the convergence criteria. The discussion reflects a need for clarification on these concepts.

Alexc475
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Homework Statement



Does The series Ʃ (2n)!/(n-1)*3^n converge or diverge?

(Starts at n=2 to infinity )

Homework Equations





The Attempt at a Solution



I tried the ratio test and nth-term test, and ended up with infinity, I'm not sure about it's convergence.
 
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Alexc475 said:

Homework Statement



Does The series Ʃ (2n)!/(n-1)*3^n converge or diverge?

(Starts at n=2 to infinity )

Homework Equations





The Attempt at a Solution



I tried the ratio test and nth-term test, and ended up with infinity, I'm not sure about it's convergence.

If the ratio you get from the ratio test goes to infinity, then the series diverges.
 
Dick said:
If the ratio you get from the ratio test goes to infinity, then the series diverges.

Ohh no wonder. Thank you! I forgot that if L>1 (L being the limit) that it converges
 
Alexc475 said:
Ohh no wonder. Thank you! I forgot that if L>1 (L being the limit) that it converges
No, if L > 1, it diverges.
 

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