Does Wave Speed on a Wire Change with Temperature Increase?

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SUMMARY

The speed of a transverse wave on a wire decreases with an increase in temperature due to the expansion of the wire. As the temperature rises, the wire lengthens, leading to a decrease in tension, which directly affects wave speed according to the equation \(v = \sqrt{\frac{F}{m/L}}\). Despite the initial assumption that increased length would increase speed, the reduction in tension ultimately results in a lower wave speed. This conclusion is supported by the relationship between wave speed, tension, and mass per unit length, where mass remains constant in this scenario.

PREREQUISITES
  • Understanding of wave mechanics, specifically transverse waves
  • Familiarity with the equation \(v = \sqrt{\frac{F}{m/L}}\)
  • Knowledge of thermal expansion and its effects on materials
  • Basic calculus for multivariable functions and partial derivatives
NEXT STEPS
  • Study the effects of temperature on material properties, focusing on thermal expansion
  • Learn about wave propagation in different media and the factors affecting wave speed
  • Explore the relationship between tension and wave speed in strings and wires
  • Investigate the derivation and application of multivariable calculus in physics problems
USEFUL FOR

Physics students, educators, and engineers interested in wave mechanics, material science, and the effects of temperature on physical systems.

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Homework Statement


A wire is strung tightly between two immovable posts. Decide whether the speed of the transverse wave on this wire would increase, decrease, or remain the same when the temperature increases. Ignore any change in the mass per unit length of the wire.

Homework Equations


$$v=\sqrt{\frac{F}{m/L}}$$
$$\Delta L=\alpha L_{0} \Delta T$$

The Attempt at a Solution


In the second equation we see that as the temperature increases the length expands. In the first equation, bigger length would imply that the speed increases. But the answer given in the textbook is "Decreases". Why?
 
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Mass per unit length of the wire ##m/L = const## (the condition of the problem). But with icreasing length, the tension force is decrease, thus, velocity is decrease.
 
sergiokapone said:
with icreasing length, the tension force is decrease
What equation gives this relation?
 
##F = AY \frac{\delta l }{l_0} ##, but initial length ##l_0## elongate due to temperature, thus F decreased.
 
Last edited:
I think you can use variations like:
$$ v(F,L) \,:\,\to\, \frac{dv}{dT} = \frac{\partial{v}}{\partial{L}}\frac{dL}{dT} - \frac{\partial{v}}{\partial{F}}\frac{dF}{dL}$$
combine your equation and that has given above.
 
theodoros.mihos said:
I think you can use variations like:
$$ v(F,L) \,:\,\to\, \frac{dv}{dT} = \frac{\partial{v}}{\partial{L}}\frac{dL}{dT} - \frac{\partial{v}}{\partial{F}}\frac{dF}{dL}$$
combine your equation and that has given above.
I have no idea how you got to this multivariable equation from what I wrote. Where did this come from?
 
A wire is strung tightly between two immovable posts.
The speed of a transverse wave on the wire is given by Equation 16.2: wave v = sqrt(F /(m / L)) .
The wire will expand because of the increase in temperature. Since the length of the wire
increases slightly, it will sag, and the tension in the wire will decrease. From Equation 16.2,
we see that the speed of the wave is directly proportional to the square root of the tension in
the wire. If we ignore any change in the mass per unit length of the wire, then we can
conclude that, when the temperature is increased, the speed of waves on the wire will
decrease.
 

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