Understanding EM Wave Reflection: Wavelength Changes Explained

In summary, the conversation discussed the problem statement of the wavelength of an electromagnetic wave after reflection at an angle on a surface. The options presented were [A] remains the same as the wavelength perpendicular to the surface, [B] remains the same in free space, [C] increases in the actual direction of propagation, and [D] decreases in the actual direction of propagation. The relevant equation C=f*lambda was also mentioned. While the correct answer appears to be [B], there is some confusion as some sources claim that [C] is the correct answer without providing an explanation.
  • #1
engnrshyckh
51
2
Homework Statement
1) The wavelength of an electromagnetic wave after reflection at angle on a surface

[A]. remains same as the wavelength perpendicular to the surface
[B].
remains same in the free space @
[C]. increases in actual direction of propagation
[D]. decreases in actual direction of propagation
2)
Relevant Equations
C=f*lambda
Problem Statement: 1) The wavelength of an electromagnetic wave after reflection at angle on a surface

[A]. remains same as the wavelength perpendicular to the surface
.
remains same in the free space @
[C]. increases in actual direction of propagation
[D]. decreases in actual direction of propagation
2)
Relevant Equations: C=f*lambda

Problem Statement: 1) The wavelength of an electromagnetic wave after reflection at angle on a surface

[A]. remains same as the wavelength perpendicular to the surface
.
remains same in the free space @
[C]. increases in actual direction of propagation
[D]. decreases in actual direction of propagation
2)
Relevant Equations: C=f*lambda

As we know the frequency of of em waves will not change so wave length alsom must nt be change so the right ans must be B but some sorces says option is C but they give no explanation why c is correct
 
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  • #2
engnrshyckh said:
some sorces [SIC] says option is C but they give no explanation why c is correct
Possibilities
1) They were talking about refraction, not reflection, and you misunderstood what they were saying
2) They don't know what they are talking about

And by the way "some sources say ... " is not a valid citation for this forum. WHO says that? Where did they say it?
 

1. What is an EM wave and how does it reflect?

An EM wave, or electromagnetic wave, is a type of energy that is made up of oscillating electric and magnetic fields. When an EM wave encounters a boundary between two mediums, a portion of the wave is reflected back into the original medium while the rest continues to travel through the new medium.

2. How does the wavelength of an EM wave change upon reflection?

The wavelength of an EM wave does not change upon reflection. The wavelength is determined by the frequency of the wave and the speed of light in the medium it is traveling through. Since the speed of light remains constant, the wavelength also remains constant.

3. What determines the angle at which an EM wave reflects?

The angle of reflection of an EM wave is determined by the angle of incidence, which is the angle at which the wave hits the boundary between two mediums. According to the law of reflection, the angle of incidence is equal to the angle of reflection.

4. How does the reflection of an EM wave affect its intensity?

The intensity of an EM wave is affected by the amount of energy that is reflected back. The more energy that is reflected, the lower the intensity of the wave will be. This is because the reflected energy is not reaching the intended destination and is instead being redirected in a different direction.

5. Can EM wave reflection be used for practical applications?

Yes, EM wave reflection is used in various practical applications such as radar, sonar, and medical imaging. By analyzing the reflected waves, scientists and engineers can gather information about the properties and boundaries of different materials and objects.

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