- #1
JG89
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Question: Let [tex] f: \mathbb{R}^3 \rightarrow \mathbb{R} [/tex] be given by [tex] f(x,y,z) = sin(xyz) + e^{2x + y(z-1)} [/tex]. Show that the level set [tex] \{ f = 1 \} [/tex] can be solved as [tex] x = x(y,z) [/tex] near [tex] (0,0,0) [/tex] and compute [tex] \frac{\partial x}{\partial y} (0,0) [/tex] and [tex] \frac{\partial x}{\partial z} (0,0,0) [/tex].
I don't understand this question. I know what the level set is. It will be the set of points (x,y,z) such that f(x,y,z) = 1. I don't understand what they mean by, show that the level set can be solved as x = x(y,z) near (0,0,0). Any help?
I don't understand this question. I know what the level set is. It will be the set of points (x,y,z) such that f(x,y,z) = 1. I don't understand what they mean by, show that the level set can be solved as x = x(y,z) near (0,0,0). Any help?