Dont understand how they did this derivative

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SUMMARY

The discussion revolves around the calculation of the second derivative of a function, specifically k = (d²I)/dr², where I(r) = (-GM/r) + (j²/2r²). The confusion arises from the transformation of terms during differentiation, particularly why the terms become GM/r² and (j²/r³) instead of their original forms. The correct application of the chain rule and the product rule in calculus is essential for understanding these transformations. The final answer derived is (-2GM/r³) + (3j²/r⁴).

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Homework Statement


Dont understand how they did this derivative



Homework Equations


k=(d^2 (I))/dr^2
were(I)(r)=(-gm/r)+(j^2)/2r^2


The Attempt at a Solution



so using the k =... they got [d/dr((GM/r^2)-((j^2)/r^3)
than they got (-2GM/r^3)+((3j^2)/r^4) as answer I know how they got this but don't see how they got the first part like why its GM/r^2 and not -GM/r and why ((j^2)/r^3) and not (j^2)/2r^2 was thinking maybe they multiply and r because its dr^2 but what happen to the 2 in (j^2)/2r^2
thxs
 
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hi leonne! :smile:

(you must start using the X2 icon just above the Reply box … your post is very difficult to read :redface:)
leonne said:
… than they got (-2GM/r^3)+((3j^2)/r^4) as answer I know how they got this but don't see how they got the first part like why its GM/r^2 and not -GM/r and why ((j^2)/r^3) and not (j^2)/2r^2 was thinking maybe they multiply and r because its dr^2 but what happen to the 2 in (j^2)/2r^2

i'm confused :confused:

you do know that d2I/dr2 is d/dr of dI/dr ?
 
o ok I get it now just take the derivative 2 times ill use the x2 next time lol keep on forgetting thxs
 

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