Don't understand this limit change in a ratio test

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SUMMARY

The discussion centers on understanding the limit change in the ratio test, specifically how the denominator transitions from (2/n+2)(2/n+1) to (2+1/n) when evaluating limits. Participants clarify that the correct approach involves dividing both the numerator and denominator by n² rather than merely converting n's into reciprocals. This method is essential for accurately determining the limit as n approaches infinity, as the highest degree terms dictate the behavior of the series.

PREREQUISITES
  • Understanding of power series
  • Familiarity with limits in calculus
  • Knowledge of algebraic manipulation of fractions
  • Concept of asymptotic behavior in sequences
NEXT STEPS
  • Study the application of the ratio test in power series convergence
  • Learn about limits involving polynomial expressions
  • Explore techniques for simplifying rational expressions
  • Investigate the concept of dominant terms in limits
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Students studying calculus, particularly those focusing on series convergence, as well as educators looking to clarify the ratio test methodology.

saybrook1
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Homework Statement


I would like to understand how the limit was changed in the ratio test from step 1 to step 2 in the image that I've posted. I thought that the denominator would look like (2/n+2)(2/n+1) in step 2 since it looks like we are just turning the n's into reciprocals. Any help here would be greatly appreciated. Thank you very much as always.

Homework Equations


Power series, limits, reciprocals.

The Attempt at a Solution


I've tried to figure out why the argument in the second set of parentheses in the denominator becomes (2+1/n) instead of (2/n+1) once the limit is changed from infinity to zero in between steps 1 and 2. Just with brute force algebra I couldn't figure out how they went from step 1 to 2.
 

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  • reciprocal limit change.jpg
    reciprocal limit change.jpg
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They're not turning the n's into reciprocals. They're dividing both the numerator and denominator by ##n^2##
 
Mastermind01 said:
They're not turning the n's into reciprocals. They're dividing both the numerator and denominator by ##n^2##
Okay, awesome. Thank you very much!
 
saybrook1 said:
Okay, awesome. Thank you very much!

Glad to be of help. I think you should mark this as solved then.
 
Mastermind01 said:
Glad to be of help. I think you should mark this as solved then.
I marked this as solved, but can I ask you how you knew that they were dividing the numerator and denominator by n^2 right away? I think I would have to expand everything to see that. Thanks again.
 
saybrook1 said:
I marked this as solved, but can I ask you how you knew that they were dividing the numerator and denominator by n^2 right away? I think I would have to expand everything to see that. Thanks again.
Because the highest degree expression (in n) in the numerator is n2 plus lower-degree terms, and the denominator is also 2nd-degree in n.
 
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Mark44 said:
Because the highest degree expression (in n) in the numerator is n2 plus lower-degree terms, and the denominator is also 2nd-degree in n.
Okay, great. Thanks!
 

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