Learning from Mistakes: Ratio Test Problem Solving

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Homework Help Overview

The discussion revolves around understanding the ratio test and factorial decomposition as part of a review for a test. The original poster expresses confusion regarding a specific step in a solution related to the factorial notation.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster questions the breakdown of (n-1)! into (n-1)(n-2)!, seeking clarification on this decomposition. Other participants provide explanations regarding factorial notation and its general form.

Discussion Status

Participants are engaged in clarifying the factorial decomposition. Some guidance has been offered, and the original poster expresses appreciation for the help received, indicating a productive exchange.

Contextual Notes

The original poster is preparing for a test and is working through practice problems, which may impose certain constraints on the depth of understanding expected.

mmont012
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Homework Statement


I'm reviewing for a test and working on the practice problems for the ratio test that Pauls Online Notes gives. So here is given problem:
eq0001MP.gif


Here is his solution for the problem:
eq0002MP.gif
2. The attempt at a solution
I worked this out before I looked at the solution and I got it wrong. I had it right up until the 4th step. Can someone explain this step to me? I don't understand why the (n-1)! is broken up into (n-1)(n-2)! Isn't this supposed to be the decomposition of (n-2)!? I'm sorry if this is a stupid question, I'm just trying to learn from my mistakes so that I won't do this again.

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Not sure I understand your question; (n-1)! =(n-1)(n-2)...2.1= (n-1)[(n-2)(n-3)...2.1]= (n-1)(n-2)! is a decomposition of (n-1)!
 
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Then what is the decomposition on (n-2)! ?
 
In this format, it is (n-2)(n-3)! . In general, (n-k)!= (n-k)(n-k-1)! if n>k, to avoid a -1!.
 
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Thank you so much! This helps me out tremendously!
 
Glad it helped, mmont012.
 

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