Doppler effect and concept of Beat Problem

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SUMMARY

The discussion centers on calculating the frequency of beats heard by a cyclist with a bell ringing at 658.8 Hz as they approach a wall at a speed of 3.18 m/s. The correct application of the Doppler effect formula, f' = f(c + v0) / (c - vs), yields a modified frequency of 665 Hz when the cyclist is moving towards the wall. The reflected sound frequency is then calculated as 671.2 Hz, resulting in a beat frequency of 12.4 Hz. This solution confirms the correct understanding of the Doppler effect and beat frequency calculation.

PREREQUISITES
  • Understanding of the Doppler effect and its formula
  • Knowledge of sound wave frequency and speed
  • Familiarity with the concept of beat frequency
  • Basic algebra for solving equations
NEXT STEPS
  • Study the Doppler effect in different mediums, such as water and air
  • Learn about the applications of beat frequency in acoustics
  • Explore advanced topics in wave interference and sound reflection
  • Investigate the effects of varying observer and source velocities on frequency perception
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Physics students, educators, and anyone interested in sound wave behavior, particularly in relation to the Doppler effect and beat frequencies.

MMONISM
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Homework Statement


A cyclist with a bell ringing with a frequency of 658.8 Hz drives towards a wall with a speed of 3.18 ms-1. Just before colliding with the wall the cyclist hears beats, due to the bell itself and the reflection of the sound from the wall. What is the frequency of beats detected by the observer? Assume that the velocity of sound in air is 343 ms-1.
Cyclist_bell_wall.jpg


Homework Equations


f'=f(c+v0)/(c-vs)
fbeat = f1 - f2

The Attempt at a Solution


f'=f(c+v0)/(c-vs)=f(c)/(c-3.18 )=665 Hz
and I am stuck here, I used fbeat = 665 - 658.8 = 6.2 Hz which is incorrect. Could someone help me please?
 
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MMONISM said:

Homework Statement


A cyclist with a bell ringing with a frequency of 658.8 Hz drives towards a wall with a speed of 3.18 ms-1. Just before colliding with the wall the cyclist hears beats, due to the bell itself and the reflection of the sound from the wall. What is the frequency of beats detected by the observer? Assume that the velocity of sound in air is 343 ms-1.View attachment 84371

Homework Equations


f'=f(c+v0)/(c-vs)
fbeat = f1 - f2

The Attempt at a Solution


f'=f(c+v0)/(c-vs)=f(c)/(c-3.18 )=665 Hz
and I am stuck here, I used fbeat = 665 - 658.8 = 6.2 Hz which is incorrect. Could someone help me please?

The wall "observes" sound from the cyclist, a moving source, which is at frequency higher than the original. It reflects sound with the modified frequency, and it is heard by the cyclist, as moving observer.
 
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ehild said:
The wall "observes" sound from the cyclist, a moving source, which is at frequency higher than the original. It reflects sound with the modified frequency, and it is heard by the cyclist, as moving observer.
Ok, so f'=f(c+v0)/(c-vs)=f(c)/(c-3.18 )=665 Hz
f''=f'(c+3.18)/(c)=671.2Hz
fbeat = 671.2 - 658.8 = 12.4 Hz
Is this correct now?
 
I think it is right.
 
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