Doppler effect and concept of Beat Problem

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Homework Help Overview

The problem involves a cyclist ringing a bell with a frequency of 658.8 Hz while moving towards a wall at a speed of 3.18 m/s. The cyclist hears beats due to the sound of the bell and its reflection from the wall, with the speed of sound in air given as 343 m/s. The objective is to determine the frequency of the beats detected by the observer.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of the Doppler effect to find the frequency of the sound as perceived by the wall and the subsequent reflection heard by the cyclist. There is a focus on the calculations leading to the determination of the beat frequency.

Discussion Status

Some participants have provided calculations for the modified frequency heard by the cyclist after the sound reflects off the wall. There is an ongoing exploration of whether the calculated beat frequency is correct, with some expressing uncertainty about the results.

Contextual Notes

Participants are working under the assumption that the equations for the Doppler effect are correctly applied, and there is a focus on the interpretation of the frequencies involved in the beat calculation.

MMONISM
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Homework Statement


A cyclist with a bell ringing with a frequency of 658.8 Hz drives towards a wall with a speed of 3.18 ms-1. Just before colliding with the wall the cyclist hears beats, due to the bell itself and the reflection of the sound from the wall. What is the frequency of beats detected by the observer? Assume that the velocity of sound in air is 343 ms-1.
Cyclist_bell_wall.jpg


Homework Equations


f'=f(c+v0)/(c-vs)
fbeat = f1 - f2

The Attempt at a Solution


f'=f(c+v0)/(c-vs)=f(c)/(c-3.18 )=665 Hz
and I am stuck here, I used fbeat = 665 - 658.8 = 6.2 Hz which is incorrect. Could someone help me please?
 
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MMONISM said:

Homework Statement


A cyclist with a bell ringing with a frequency of 658.8 Hz drives towards a wall with a speed of 3.18 ms-1. Just before colliding with the wall the cyclist hears beats, due to the bell itself and the reflection of the sound from the wall. What is the frequency of beats detected by the observer? Assume that the velocity of sound in air is 343 ms-1.View attachment 84371

Homework Equations


f'=f(c+v0)/(c-vs)
fbeat = f1 - f2

The Attempt at a Solution


f'=f(c+v0)/(c-vs)=f(c)/(c-3.18 )=665 Hz
and I am stuck here, I used fbeat = 665 - 658.8 = 6.2 Hz which is incorrect. Could someone help me please?

The wall "observes" sound from the cyclist, a moving source, which is at frequency higher than the original. It reflects sound with the modified frequency, and it is heard by the cyclist, as moving observer.
 
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ehild said:
The wall "observes" sound from the cyclist, a moving source, which is at frequency higher than the original. It reflects sound with the modified frequency, and it is heard by the cyclist, as moving observer.
Ok, so f'=f(c+v0)/(c-vs)=f(c)/(c-3.18 )=665 Hz
f''=f'(c+3.18)/(c)=671.2Hz
fbeat = 671.2 - 658.8 = 12.4 Hz
Is this correct now?
 
I think it is right.
 
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