Calculating x for Perpendicular Vectors A and B: Dot and Cross Product Homework

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SUMMARY

The discussion revolves around determining the value of x for vectors A=(x,3,1) and B=(x,-x,2) such that the vector C=(10,-4,-4) is perpendicular to both A and B. Participants explored using the cross product A x B and the dot product A · C = 0 and B · C = 0. The calculations yielded conflicting values for x: 1.6 from A · C and 0.4 from B · C, indicating a potential issue with the problem statement itself. The consensus suggests that the problem may be misprinted, as no consistent value for x exists.

PREREQUISITES
  • Understanding of vector operations, specifically cross product and dot product.
  • Familiarity with vector notation and properties of perpendicular vectors.
  • Basic algebra skills for solving equations involving variables.
  • Knowledge of linear algebra concepts related to vector spaces.
NEXT STEPS
  • Review the properties of vector cross products and their geometric interpretations.
  • Study the conditions for vector perpendicularity using dot products.
  • Examine common pitfalls in vector calculations, particularly with variable components.
  • Investigate potential errors in problem statements and how to verify their accuracy.
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Outrageous
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Homework Statement


A=(x,3,1) ,B=(x,-x,2)
Determine the value of x if the vector perpendicular to A and B is given by C=(10,-4,-4)


Homework Equations





The Attempt at a Solution


Find A cross B , let A cross B be D . Then D cross C = zero (since they are perpendicular to both A and B) . This sounds logic but there will not be an answer for x. What is wrong?
Then I tried to use dot product A dot C=0, and B dot C=0. Yet the answer of two x are different.
Please guide. Thanks
 
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You haven't shown your calculations. But perhaps there is no real value of x that works. Perhaps the problem is mis-printed or copied incorrectly.
 
LCKurtz said:
You haven't shown your calculations. But perhaps there is no real value of x that works. Perhaps the problem is mis-printed or copied incorrectly.

So the both ways to solve the problem are correct?
 
Outrageous said:
So the both ways to solve the problem are correct?

I didn't say that. I haven't worked the problem; that's your job. If you want me to comment on what you did you need to show your work.
 
The first way
 

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Sorry a, my camera not good.
 
Please look at the picture, I don't know why I can't upload more picture.
The second way, A dot C = 0 , x= 1.6
B dot C = 0 , x= 0.4
Thanks
 
Last edited:
I won't try to read upside down. But if your arithmetic is correct and you get different values for ##x##, that would tell you there is no solution. Like I said earlier, perhaps the problem is mis-printed or copied incorrectly.
 
Thanks
 
  • #10
I would like to remark that your approach with the cross product is over-complicated. Once you found C = A x B, and assume that C is parallel with D, you can say C = k D, where k is some number. You do not need to cross-multiply C and D, you just need to confirm that C = k D is possible.
 
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  • #11
voko said:
I would like to remark that your approach with the cross product is over-complicated. Once you found C = A x B, and assume that C is parallel with D, you can say C = k D, where k is some number. You do not need to cross-multiply C and D, you just need to confirm that C = k D is possible.

Really easier. But I think the question have some problems. Thank you.
 

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